Leetcode11——Container With Most Water

文章作者：Tyan
博客：noahsnail.com  |  CSDN  |  简书

1. Description

2. Solution

• Brute Force

class Solution {
public:
    int maxArea(vector<int>& height) {
        int length = height.size();
        int maxArea = 0;
        int area = 0;
        for(int i = 0; i < length; i++) {
            for(int j = i + 1; j < length; j++) {
                area = (j - i) * (height[i]<height[j]?height[i]:height[j]);
                if(maxArea < area) {
                    maxArea = area;
                }
            }
        }
        return maxArea;
    }
};

• Two Pointer Approach

  class Solution {
  public:
      int maxArea(vector<int>& height) {
          int i = 0;
          int j = height.size() - 1;
          int maxArea = 0;
          int area = 0;
          while(i < j) {
              area = (j - i) * (height[i]<height[j]?height[i]:height[j]);
              if(maxArea < area) {
                  maxArea = area;
              }
              height[i]<height[j]?i++:j--;
          }
          return maxArea;
      }
  };

参考资料

1. https://leetcode.com/problems/container-with-most-water/description/