Leetcode 914. X of a Kind in a Deck of Cards

文章作者：Tyan
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1. Description

2. Solution

解析：Version 1，统计元素个数，遍历所有可能的分割数量，下限为2，上限为最少的元素个数，如果满足条件，返回True。

• Version 1

class Solution:
    def hasGroupsSizeX(self, deck: List[int]) -> bool:
        stat = collections.Counter(deck)
        for j in range(2, min(stat.values()) + 1):
            flag = True
            for val in stat.values():
                if val % j != 0:
                    flag = False
                    break
            if flag:
                return True
        return False

Reference

1. https://leetcode.com/problems/x-of-a-kind-in-a-deck-of-cards/