Leetcode 105. Construct Binary Tree from Preorder and Inorder Traversa

文章作者：Tyan
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1. Description

2. Solution

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    TreeNode* buildTree(vector<int>& preorder, vector<int>& inorder) {
        int current = 0;
        return build(preorder, inorder, current, 0, preorder.size() - 1);
    }
    
    
private:
    TreeNode* build(vector<int>& preorder, vector<int>& inorder, int& current, int start, int end) {
        if(current == preorder.size() || start > end) {
            return nullptr;
        }
        int value = preorder[current];
        TreeNode* node = new TreeNode(value);
        int index = 0;
        for(int i = start; i <= end; i++) {
            if(inorder[i] == value) {
                index = i;
                break;
            }
        }
        current++;
        node->left = build(preorder, inorder, current, start, index - 1);
        node->right = build(preorder, inorder, current, index + 1, end);
        return node;
    }
};

Reference

1. https://leetcode.com/problems/construct-binary-tree-from-preorder-and-inorder-traversal/description/