Leetcode 151. Reverse Words in a String

文章作者：Tyan
博客：noahsnail.com  |  CSDN  |  简书

1. Description

2. Solution

• First Try

class Solution {
public:
    void reverseWords(string &s) {
        removeSpace(s);
        reverseWords(s, 0, s.size() - 1);
        int index = -1;
        int start = 0;
        while((index = s.find(" ", index + 1)) != string::npos) {
            reverseWords(s, start, index - 1);
            start = index + 1;
        }
        reverseWords(s, start, s.size() - 1);
    }
    
    void reverseWords(string& s, int start, int end) {
        for(int i = start, j = end; i < j; i++, j--) {
            char temp = s[i];
            s[i] = s[j];
            s[j] = temp;
        }
    }
    
    void removeSpace(string &s) {
        s.erase(0, s.find_first_not_of(" "));
        s.erase(s.find_last_not_of(" ") + 1);
        int i = 0;
        int j = 1;
        while(j < s.size()) {
            if(s[j] == ' ' && s[j - 1] != ' ') {
                i = j;
            }
            if(s[j] == ' ' && s[j + 1] != ' ' && i != j) {
                s.erase(i + 1, j - i);
                j = i;
            }
            j++;
        }
    }
};

• Second Try

  class Solution {
  public:
      void reverseWords(string &s) {
          reverseWords(s, 0, s.size() - 1);
          removeAndRemoveMiddleSpace(s);
      }
      
      void reverseWords(string& s, int start, int end) {
          for(int i = start, j = end; i < j; i++, j--) {
              char temp = s[i];
              s[i] = s[j];
              s[j] = temp;
          }
      }
      
      void removeAndRemoveMiddleSpace(string &s) {
          s.erase(0, s.find_first_not_of(" "));
          s.erase(s.find_last_not_of(" ") + 1);
          int i = 0;
          int j = 1;
          int k = 0;
          while(j < s.size()) {
              if(s[j] == ' ' && s[j - 1] != ' ') {
                  reverseWords(s, k, j - 1);
                  i = j;
              }
              if(s[j] == ' ' && s[j + 1] != ' ') {
                  if(i != j) {
                      s.erase(i + 1, j - i);
                      j = i;
                  }
                  k = j + 1;
              }
              j++;
          }
          reverseWords(s, k, j - 1);
      }
  };

Reference

1. https://leetcode.com/problems/reverse-words-in-a-string/description/